(1-1/n)^(n-1)
=(1-1/n)^-(1-n)
=[1+1/(n-1)]^(1-n) 再答: (1-1/n)^(n-1)
=(1-1/n)^-(1-n)
=[(n-1)/n]^-(1-n)
=[n/(n-1)]^(1-n)
=[1+1/(n-1)]^(1-n)
=[1+1/(n-1)]^-(n-1)
=1/ {[1+1/(n-1)]^(n-1)}
∵limx→∞,(1+1/x)^x=e
imx→∞, {[1+1/(n-1)]^(n-1)}=e
limx→∞,1/ {[1+1/(n-1)]^(n-1)}=1/e