问题描述:
帮我看看求二次函数的C语言程序,要求要用函数来写,
#include
#include
double t,x1,x2;
void main()
{
void situ1(double a,double b,double c);
void situ2(double a,double b,double c);
void situ3();
double x,a,b,c;
scanf("%lf%lf%lf",&a,&b,&c);
if (a=0)
x=c/b;
else
{
\x05t=b*b-4*a*c;
\x05if (t>0)
\x05\x05situ1(a,b,c);
\x05else if(t=0)
\x05\x05situ2(a,b,c);
\x05else
\x05\x05situ3();
\x05
}
}
void situ1(double a,double b,double c)
{
\x05x1=(-b+sqrt(t))/(2*a);
\x05x2=(-b-sqrt(t))/(2*a);
\x05printf("%lf\t%lf",x1,x2);
}
void situ2(double a,double b,double c)
{
\x05x1=x2=(-b+sqrt(t))/(2*a);
\x05printf("%lf\t%lf",x1,x2);
}
void situ3()
{
\x05printf("没有实根");
}
#include
#include
double t,x1,x2;
void main()
{
void situ1(double a,double b,double c);
void situ2(double a,double b,double c);
void situ3();
double x,a,b,c;
scanf("%lf%lf%lf",&a,&b,&c);
if (a=0)
x=c/b;
else
{
\x05t=b*b-4*a*c;
\x05if (t>0)
\x05\x05situ1(a,b,c);
\x05else if(t=0)
\x05\x05situ2(a,b,c);
\x05else
\x05\x05situ3();
\x05
}
}
void situ1(double a,double b,double c)
{
\x05x1=(-b+sqrt(t))/(2*a);
\x05x2=(-b-sqrt(t))/(2*a);
\x05printf("%lf\t%lf",x1,x2);
}
void situ2(double a,double b,double c)
{
\x05x1=x2=(-b+sqrt(t))/(2*a);
\x05printf("%lf\t%lf",x1,x2);
}
void situ3()
{
\x05printf("没有实根");
}
问题解答:
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