已知函数f(x)=sinx（sinx＋根号3cosx）,x∈【0,拍/2】.

f(x)=sinx(sinx+√3cosx)
=(sinx)^2+根号3sinxcosx
=(1-cos2x)/2+根号3/2 sin2x
=sin2x*cosπ/6-cos2x sinπ/6+1/2
=sin(2x-π/6)+1/2
其中x∈[0,π/2],那么2x-π/6属于[-π/6,5π/6]
所以,-1/2