问题描述: 求y=(3X⒉+2)(X-5)的导数求y=(5x3-7)(3x+8)的导数求y=x/x2+1的导数 1个回答 分类:数学 2014-12-04 问题解答: 我来补答 y=(3x^2+2)(x-5)y'=(3x^2+2)'*(x-5)+(3x^2+2)*(x-5)'=6x(x-5)+1*(3x^2+2)=6x^2-30x+3x^2+2=9x^2-30x+2y=(5x^3-7)(3x+8)=15x^4+40x^3-21x-56y'=15*4x^3+40*3x^2-21*1-0=60x^3+120x^2-21y=x/(x^2+1)y'=[x'*(x^2+1)-x*(x^2+1)']/(x^2+1)^2=[(x^2+1)+x*2x]/(x^2+1)^2=(3x^2+1)/(x^2+1)^2 展开全文阅读