问题描述: 求y=x^3/(x^2-3x-4)的高阶导数y(n) 1个回答 分类:综合 2014-11-11 问题解答: 我来补答 y=x^3/(x^2-3x-4)=x^3/(x+1)(x-4)=(x^3+1-1)/(x+1)(x-4)=(x^2+x+1)/(x-4)-1/(x+1)(x-4)=(x^2-4x+5x-20+21)/(x-4)-1/5[1/(x-4)-1/(x+1)]=x+5+21/(x-4)-1/5[1/(x-4)-1/(x+1)]=x+5+104/5*1/(x-4)+1/5*1/(x+1)接着再套求导公式即可! 展开全文阅读