C语言或者C++,统计产生的100个随机数中(0,16838) 和(16839,32767)区中的比例

#include
#include
#include
int main(){
srand(time(0));
int a[100] = {0};
float n1,n2;
int count1 = 0,count2 = 2;
int i,j;
for(i = 0;i < 100;i ++){
a[i] = rand();
for(i = 0;i 0&& a[i] < 16838)
count1 ++;
if(a[i] >16839&& a[i] < 32767)
count2 ++;
}
n1 = count1/100;
n2 = count2/100;
printf("%f %f",n1,n2);
}