如图在直角三角形abc中角c等于90度,bd平分角abc,且交ac于点d,若ap平分角bac且交bd于p,求角bpa的度

∠BPA=180°-∠ABP-BAP=180°-(∠ABP+∠BAP)
=180°-1/2(∠ABC+∠BAC)=180°-1/2(180°-∠C)=90°+1/2∠C=135°