(要详细的过程)用公式法解下列方程：(1) x^2+x-12=0 ; (2)x^2-√2（x）-1/4=0 ; (3)

(1) x^2+x-12=0 => (x+4)(x-3)=0 => x1=-4,x2=3
(2) x^2-√2（x）-1/4=0 => x^2-√2(x)+ [(√2)/2]^2-[(√2)/2]^2-1/4=0
=> [x-(√2)/2]^2-1/2-1/4=0 => [x-(√2)/2]^2=3/4 => x=±(√3)/2+(√2)/2
=> x1=(√3-√2)/2,x2=(√2-√3)/2
(3) x^2+4x+8=2x+11 => x^2+2x+1=4 =>(x+1)^2=4 => x= -1±2
(4) x(x-4)=2-8x => x^2-4x=2-8x => x^2 +4x -2=0 => x^2+4x+4=6 => (x+2)^2=6 => x=-2±√6
(5) X^2+2x=0 => x（x+2)=0 => x1=0,x2=-2
(6) X^2+2√5 x+10=0 => x^2+2√5 x + (√5)^2-5+10=0 => (x+√5)^2= -5 一个数的平方不可能是负数所以此题无解