问题描述： (1/x-3)-(6/x^2-9)-(x-1/6+2x) 1个回答 分类：数学 2014-11-30 问题解答： 我来补答 (1/x-3)-(6/x^2-9)-(x-1/6+2x)=1/(x-3)-6/[(x-3)(x+3)]-(x-1)/[2(x+3)]=[2(x+3)-12-(x-1)(x-3)]/[2(x-3)(x+3)]=(2x+6-12-x²+4x-3)/[2(x-3)(x+3)]=(-x²+6x-9)/[2(x-3)(x+3)]=-(x-3)²/[2(x-3)(x+3)]=(3-x)/[2(x+3)] 展开全文阅读
