问题描述: (x的平方-9分之x+3+x的平方+x-6分之x)乘(x+3) 1个回答 分类:数学 2014-11-12 问题解答: 我来补答 [ (x+3) / (x² -9 ) + x / (x²+x-6) ] *(x+3)= { (x+3) / [ (x+3)(x-3) ] + x / [ (x+3)(x-2) ] } *(x+3)= (x+3)/(x-3) + x / (x-2)= [ (x+3)(x-2) + x(x-3) ] / [ (x-3)(x-2) ]= [ x² +x - 6 + x² - 3x ] / [ (x-3)(x-2) ]= [ 2x² - 2x - 6 ] / [ (x-3)(x-2) ]= 2 ( x² - x - 3 ) / (x² - 5x + 6)请确认题目无误 展开全文阅读