求回答这是个计算题目.如下a^﹣2bc^﹣1÷【﹣b^2c】^3下面是分解因式.三个.如下﹣25x^2y^2+10xy-

a^﹣2bc^﹣1÷【﹣b^2c】^3
=a^-2bc^-1×(-b^-6c^-3)
=-a^-2b^-5c^-4
﹣25x^2y^2+10xy-1
=-(25x^2y^2-10xy+1)
=-(5xy-1)^2
﹣16a^4+b^4
=(b^2+4a^2)(b^2-4a^2)
=(b^2+4a^2)(b+2a)(b-2a)
[x^2-2]^2-4[x^2-2]+4
=(x^2-2-2)^2
=(x^2-4)^2
=(x+2)^2(x-2)^2