1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512

问题描述:

1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512
亲,各位大侠们,赶快救我吧!
1个回答 分类:数学 2014-11-05

问题解答:

我来补答
1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512
这是首项为1,公比为-1/2的等比数列前10项和,
由公式即有:
1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512
=[1-(-1/2)^10]*1/(1+1/2)
=(2/3)*[1-(1/2)^10]
=(2/3)*1023/1024
=1023/1536
=341/512
 
 
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