问题描述: 1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512亲,各位大侠们,赶快救我吧! 1个回答 分类:数学 2014-11-05 问题解答: 我来补答 1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512这是首项为1,公比为-1/2的等比数列前10项和,由公式即有:1-1/2+1/4-1/8+1/16-1/32+1/64-1/128+1/256-1/512=[1-(-1/2)^10]*1/(1+1/2)=(2/3)*[1-(1/2)^10]=(2/3)*1023/1024=1023/1536=341/512 展开全文阅读