如图,在三角形ABC中,BD平分∠ABC,CD平分三角形ABC的外角∠ACE,BD,CD交于点D,图一中∠A=90°,

∠D=180-1/2∠ABC-1/2∠ACE-∠ACB
=180-1/2∠ABC-1/2(180-∠ACB)-∠ACB
=180-1/2∠ABC-1/2∠ACB+90
=90-1/2∠ABC-1/2∠ACB
=1/2∠A