数列递推公式求通项A(n+1)=(n+1)An+1 怎么求通项,A1=1 或者告诉我这个怎么求和(n+1)*n*(n-1

问题描述:

数列递推公式求通项
A(n+1)=(n+1)An+1 怎么求通项,
A1=1
或者告诉我这个怎么求和
(n+1)*n*(n-1)``````````````1+
(n+1)*n*`````````````````2+
(n+1)*n*``````````````3+
````````````````````
(n+1)*n+
(n+1)
1个回答 分类:数学 2014-11-15

问题解答:

我来补答
迭代法.楼上花了功法,但是不对,如果是A(n+1)+1/(n+1)=(n+1)[An+(1/n)]倒还可以构造Bn={An+1/n},但也不是等比数列啊.
 
 
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