问题描述: 当n为何整数时,关于x的二次方程x^2-3nx+2n^2-6=0的两根都为整数 1个回答 分类:数学 2014-11-16 问题解答: 我来补答 变形得:(x-2n)*(x-n)=6分组讨论.x-2n = 6; x-n = 1x-2n = -6; x-n = -1x-2n = 3; x-n = 2x-2n = -3; x-n = -2x-2n = 2; x-n = 3x-2n = -2; x-n = -3x-2n = 1; x-n = 6x-2n = -1; x-n = -6解方程:得n=正负1;n=正负5 展开全文阅读