问题描述: 化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)] 1个回答 分类:数学 2014-11-23 问题解答: 我来补答 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc(π-α)]= [(-sinα)\tanα] ×[(-cotα)\(-cosα)]×[secα\cscα]= [(-sinα)×cosα\sinα] ×[(cosα\sinα)\cosα)]×(sinα\cosα)=-cosα×(1\sinα)×(sinα\cosα)=-1 展开全文阅读