问题描述: 1个回答 分类:数学 2015-02-01 问题解答: 我来补答 解题思路: =a^2b/2-3a^2b/2+6abc+2a^2c-3abc解题过程: 解:=1/2a^2b-【3/2a^2b-6abc-2a^2c】-3abc =1/2a^2b-3/2a^2b+6abc+2a^2c-3abc =-a^2b+2a^2c+3abc =a^2(2c-b)+3abc =1*4+9/2 =4+9/2 =8又1/2 展开全文阅读