问题描述: 关于复合函数求导√((x-1)/(x+1)) 1个回答 分类:数学 2014-12-07 问题解答: 我来补答 y=√((x-1)/(x+1)) t=(x-1)/(x+1)√((x-1)/(x+1)) =√ty't=1/[2√t]t'x=[(x+1)-(x-1)]/(x+1)^2=2/(x+1)^2y"x=y't*t'x=1/[2√t]*2/(x+1)^2=1/[√(x^2-1)*(x+1)] 展开全文阅读