问题描述: 求微积分方程(1+y)dx-(1-x)dy=0的通解 1个回答 分类:数学 2014-11-07 问题解答: 我来补答 (1 + y) dx - (1 - x) dy = 0(1 + y) dx = (1 - x) dy[1/(1 - x)]dx =[1 /(1 + y)]dyd(ln(1 - x))=d(ln(1 + y))ln(1 - x) + C1 = ln(1 + y) (C1为任意实数)1 + y = e^[ln(1 - x) + C1]y = C*(1 - x) - 1 (C为任意实数) 展开全文阅读