若x=(1-t)/(1+t) y=(2-3t)/(3-2t),用x的代数式表示y

x+xt=1-t
t=(1-x)/x+1)
3y-2yt=2-3t
t=(3y-2)/(2y-3)
(3y-2)/(2y-3)=(1-x)/(x+1)
3xy+3y-2x-2=2y-3-2xy+3x
5xy+y=5x-1
y=(5x-1)/(5x+1)