汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到

问题描述:

汶川地震,震后2小时,某武警率部队从 XX县出发 去营救,13日凌晨1:15分动身,但途中遇到了麻烦,他们决定步行,但到达理县后因救人而耽误了1小时.随后,先派遣分队将步行速度提高了9分之1.于13日23时15分到达汶川~
求先遣分队从理县到汶川的平均速度是多少?
我会加的!
还求 从开始到理县的时间 从理县到汶川的速度和时间 (这是表格)
从开始到理县是30千米,从理县到汶川是60千米
是求 从XX县到理县的时间 从理县到汶川的速度和时间
求先遣分队从 理县 到汶川的平均速度是多少?
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1个回答 分类:数学 2014-09-23

问题解答:

我来补答
设先遣分队从理 到汶川的平均速度是X千米每时
用时22小时,但步行时间T=22-1=21小时
由题意列方程:(30/x)+[60/(x+x/9)]=21
解方程得:84/x=21
x=4千米每时
答:先遣分队从理 到汶川的平均速度是4千米每时.(不好意思刚看到题目,希望对有所帮助)
 
 
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