设f(x)为奇函数,且当x>0时,f(x)=log1/2x.(1)求当x

x>0,f(x)=log(1/2)x=-log2(x)
1. x0,
f(-x)=-log2(-x)=-f(x)
f(x)=log2(-x)
2. x>0,f(x)=-log2(x)