3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于

问题描述:

3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于
1个回答 分类:数学 2014-11-06

问题解答:

我来补答
先化简,再求值
3x²y-[2xy-2(xy-2/3x²y)+xy]
=3x²y-2xy+2(xy-2/3x²y)-xy
=3x²y-2xy+2xy-4/3x²y-xy
=5/3x²y-xy
=xy(5/3x-1)
将x=3,y=-1/3 代入
原式=xy(5/3x-1)=3×(-1/3)(5/3×3-1)=-1×(5-1)=-4
 
 
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