2x-6/(x-2)/[5/(x-2)-x-2]

原式=[2(x-3)/(x-2)]÷[5/(x-2)-(x+2)]
=[2(x-3)/(x-2)]÷{[5-(x+2)(x-2)]/(x-2)}
=[2(x-3)/(x-2)]÷[(5-x²+4)/(x-2)]
=[2(x-3)/(x-2)]÷[-(x+3)(x-3)/(x-2)]
=-2(x-3)(x-2)/[(x-2)(x+3)(x-3)]
=-2/(x+3)
再问： 佩服，再问一下，除号怎么打？
再答： 我用的是搜狗。。。直接打"chu“第五个就是÷