如图,AB=AC,∠BAC=90°,BD⊥AE于D,CE⊥AE于E 说明1、AD=CE 2、BD=AE

BD⊥AE,CE⊥AE
BD// CE
∠DBE = ∠ECB
∠ECB+ ∠ACB = 90 - ∠EAC
∠DBE + ∠ACB = 180 - ∠BAC - ∠ABD= 90 - ∠ABD
所以∠EAC=∠ ABD
∠BAD = 90 - ∠EAC
∠ACE = 90 - ∠EAC
所以∠BAD = ∠ACE
AB=AC
所以 三角形BAD全等ACE
AD=CE
BD=AE