问题描述: 计算1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2007)(a+2008)+1/(a+2011)(a+2012) 1个回答 分类:数学 2014-09-28 问题解答: 我来补答 1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2007)(a+2008)+1/(a+2011)(a+2012)=1/a-1/(a+1)+1/(a+1)-1/(a+2)+...+1/(a+2007)-1/(a+2008)+1/(a+2011)-1/(a+2012)=1/a-1/(a+2012)=2012/[a(a+2012)] 展开全文阅读