某个五位数被187除余52,被188除余51,那么这个自然数被22除的余数是?

x=187m+52=188n+51
187m=188n-1
m=n+(n-1)/187 令(n-1)/187=a 则m=n+a
n-1=187a n=187a+1 x=188n+51=188(187a+1)+51=35156a+188+51=35156a+239
m=187a+1+a=188a+1 x=187m+52=187(188a+1)+52=35156a+187+52=35156a+239
x>9999 35156a+239>9999 35156a>9760 a>9760/35156=0.27.
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