若方程1+2k除以9-(x的平方=k除以x-3有增根,则k=?

(1+2k)/(9-x^2)=k/(x-3)
1+2k=-k(x+3)
kx+5k+1=0
增根是x=3,或x=-3.
x=3时,k=-1/8
x=-3时,k=-1/2
k=-1/8或-1/2