问题描述: 求lim(x趋向于3时)sin(x-3)/(x的平方减9) 1个回答 分类:数学 2014-10-09 问题解答: 我来补答 lim(x趋向于3) sin(x-3)/(x*x-9)=lim(x趋向于3) sin(x-3)/[(x-3)(x+3)]=[lim(x趋向于3) sin(x-3)/(x-3)]*[lim(x趋向于3)1/(x+3) ] =1*1/6=1/6 展开全文阅读