计算:1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2006)(a+2007)

问题描述:

计算:1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2006)(a+2007)
快啊,等着救命聂!
1个回答 分类:数学 2014-12-07

问题解答:

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裂项:1/a(a+1)=1/a-1/(a+1)
1/a(a+1)+1/(a+1)(a+2)+...+1/(a+2006)(a+2007)
=1/a-1/(a+1)+1/(a+1)-1/(a+2)+...+1/(a+2006)-1/(a+2007)
=1/a-1/(a+2007)
 
 
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