问题描述: 化简三角函数.1-cos^4α-sin^4α/1-cos^6α-sin6α 我这里没加括号呀。 1个回答 分类:数学 2014-09-26 问题解答: 我来补答 没加括号的话sin^4α/1根本就没用的嘛~应该是(1-cos^4α-sin^4α)/(1-cos^6α-sin^6α) 1=sin^2α+cos^2α原式=(sin^2α+cos^2α-cos^4α-sin^4α)/(sin^2α+cos^2α-cos^6α-sin^6α)分子=sin^2α(1-sin^2α)+cos^2α(1-cos^2α)=2sin^2αcos^2α分母=sin^2α(1-sin^4α)+cos^2α(1-cos^4α)sin^2α(1-sin^4α)=sin^2α(1-sin^2α)(1+sin^2α)=sin^2αcos^2α(1+sin^2α)同理cos^2α(1-cos^4α)=sin^2αcos^2α(1+cos^2α)原式=2sin^2αcos^2α/sin^2αcos^2α(1+sin^2α+1+cos^2α)=2/3 展开全文阅读