问题描述: 已知函数f(x)=(1+cotx)sin^2x+msin(x+π/4)sin(x-π/4).当tanα=2时,f(α)=3/5,求m的值. 1个回答 分类:数学 2014-10-22 问题解答: 我来补答 cot(α)=1/2,(cscα)^2=1+1/4=5/4,(sinα)^2=4/5,f(α)=(1+1/2)*(4/5)+m[(sinα)^2-(cosα)^2]/2=6/5-(mcos2α)/2=6/5-m*[1-2(sinα)^2]/2=6/5-m(1-8/5)/2=6/5+3m/106/5+3m/10=3/5,m=-2. 展开全文阅读