问题描述: x/x-3-5x/x^2-x-6计算 1个回答 分类:数学 2014-11-20 问题解答: 我来补答 原式=[x/(x-3)]-[5x/(x²-x-6)] =[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=(x²+2x-5x)/[(x-3)(x+2)]=(x²-3x)/[(x-3)(x+2)]=[x(x-3)]/[(x-3)(x+2)]=x/(x+2) 展开全文阅读