问题描述: 求不定积分∫[(arctan√x)/(√x(1+x))]dx 1个回答 分类:综合 2014-11-17 问题解答: 我来补答 令y=√x,代入上式得:2∫y[(arctany)/(y(1+y^2))]dy=2∫[(arctany)/(1+y^2)]dy=2∫(arctany)d(arctany)=(arctany)^2+c=(arctan√x)^2+c 展开全文阅读