问题描述： (x-1/x^2+3x+2)-(6/x^2-x-2)-(x-10/x^2-4) 1个回答 分类：数学 2014-11-17 问题解答： 我来补答 =(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=(x^2-3x+2)/(x+1)(x+2)(x-2)-(6x+12)/(x+1)(x+2)(x-2)-(x^2-9x-10)/(x+1)(x+2)(x-2)=0 展开全文阅读
