先化简,在求值,{（a^2-4a+4分之a^2-4）-（2-a分之1）}÷a^2-2a分之1,其中a是方程x^2+3x+

原式={[(a+2)(a-2)/(a-2)^2+[(a-2)^2/1/(a-2)]}×a(a-2)
=[(a+2)/(a-2)+1/(a-2)]×a(a-2)
=[(a+3)/(a-2)]×a(a-2)
=a(a+3)
=a^2+3a
=-1