问题描述: 解分式方程:1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4) 1个回答 分类:数学 2014-12-09 问题解答: 我来补答 1/(x^2+3x+2)+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)1/[(x+1)(x+2)]+1/(x+2)(x+3)=(2x+5)/(x+1)(x+4)2(x+2)/[(x+1)(x+2)(x+3)]=(2x+5)/(x+1)(x+4)2/(x+3)=(2x+5)/(x+4)2x+8= (2x+5)(x+3) =2x^2+11x+152x^2+9x +7 =0(2x+7)(x+1)=0x= -7/2 展开全文阅读