问题描述: 求极限lim(x→0){(2x-sin2x)/xsin^2x} 1个回答 分类:数学 2014-10-06 问题解答: 我来补答 lim(x→0){(2x-sin2x)/(x*sin^2x)}= lim(x→0){(2x-sin2x)/(x*x^2*(sin^2x/x^2))}= lim(x→0){(2x-sin2x)/(x*x^2) * lim(x→0){(sin^2x/x^2)}= lim(x→0){(2-2cos2x)/(3x^2)= lim(x→0){(4sin2x)/(6x)= lim(x→0){(8cos2x)/(6)= 4/3 展开全文阅读