产生Fibonacci数列的头20项存入一个一维数组中,按每行4个输出数组的元素.

int a[20];
a[0] = 1; a[1] = 1;
for (int i = 2; i < 20; i++)
a[i] = a[i-1] + a[i-2];
for (int i = 0; i < 5; i++)
{
for (int j = 0; j