log2为底(x+1)

问题描述:

log2为底(x+1)
1个回答 分类:数学 2014-10-17

问题解答:

我来补答
log2[x+1]≤log4[3x+1]
定义:x+1>0 x>-1
3x+1>0 x>-1/3
log2[x+1]≤(1/2)log2[3x+1]
2log2[x+1]≤log2[3x+1]
log2[x+1]²≤log2[3x+1]
(x+1)²≤3x+1
x²+2x+1≤3x+1
x²-x≤0
x(x-1)≤0

0≤x≤1
 
 
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