问题描述：
log4(12)与log8(27)的差和log4(27)与log2(6)的差的比值为
问题解答：
我来补答
[log4(12)-log8(27)]/[log4(27)-log2(6)]
=[log2(12)/log2(4)-log2(27)/log2(8)]/[log2(27)/log2(4)-log2(6)/log2(2)]
=[log2(12)/2-log2(27)/3]/[log2(27)/2-log2(6)]
=[log2(12)/2-3log2(3)/3]/[3log2(3)/2-log2(6)]
=[log2(3*4)/2-log2(3)]/[3log2(3)/2-log2(2*3)]
=[log2(3)/2+log2(4)/2-log2(3)]/[3log2(3)/2-log2(2)-log2(3)]
=[-log2(3)/2+1]/[log2(3)/2-1]
=-1
=[log2(12)/log2(4)-log2(27)/log2(8)]/[log2(27)/log2(4)-log2(6)/log2(2)]
=[log2(12)/2-log2(27)/3]/[log2(27)/2-log2(6)]
=[log2(12)/2-3log2(3)/3]/[3log2(3)/2-log2(6)]
=[log2(3*4)/2-log2(3)]/[3log2(3)/2-log2(2*3)]
=[log2(3)/2+log2(4)/2-log2(3)]/[3log2(3)/2-log2(2)-log2(3)]
=[-log2(3)/2+1]/[log2(3)/2-1]
=-1
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