问题描述: 1/3+1/15+1/35+1/63+1/99+1/143的简便算法(写过程) 1个回答 分类:数学 2014-10-29 问题解答: 我来补答 原式=1/1*3+1/(3*5)+1/(5*7)+1/(7*9)+1/(9*11)+1/(11*13)=1/2(1-1/3)+1/2(1/3-1/5)+1/2(1/5-1/7)+1/2(1/7-1/9)+1/2(1/9-1/11)+1/2(1/11-1/13)=1/2(1-1/13)=6/13 展开全文阅读