问题描述:
英文数学题一道+函数一道
1.An ellipse is the locations of points where the sum of the distances to two fixed points is constant.
Show that the ellipse where the sum of the distances (1,0) and (0,1) is 二倍根二 can be written as
(x^2)/(a^2) + (y^2)/(b^2) = 1
where a and be are constants to be determined.
2.求所有满足条件的函数
a) f(x+y) + f(x-y) = 2(x^2) + 2(y^2)
b) g(x+t) - g(x-t) = 4xt
第一题的第二个点是(-1,0)||
1.An ellipse is the locations of points where the sum of the distances to two fixed points is constant.
Show that the ellipse where the sum of the distances (1,0) and (0,1) is 二倍根二 can be written as
(x^2)/(a^2) + (y^2)/(b^2) = 1
where a and be are constants to be determined.
2.求所有满足条件的函数
a) f(x+y) + f(x-y) = 2(x^2) + 2(y^2)
b) g(x+t) - g(x-t) = 4xt
第一题的第二个点是(-1,0)||
问题解答:
我来补答展开全文阅读