问题描述:
c语言写的兔子繁殖- 斐波那契数列.每次只显示前两个.
#include "stdafx.h"
#include "stdio.h"
void function(int a)
{
\x05long sum1,sum2,sum3;
\x05if(a>=1)
\x05{
\x05\x05sum1=1;
\x05\x05printf("M.1%10ld",sum1);
\x05}
\x05if(a>=2)
\x05{
\x05\x05sum2=1;
\x05\x05printf("M.2%10ld",sum2);
\x05}
\x05else
\x05\x05for(int i =3;i
#include "stdafx.h"
#include "stdio.h"
void function(int a)
{
\x05long sum1,sum2,sum3;
\x05if(a>=1)
\x05{
\x05\x05sum1=1;
\x05\x05printf("M.1%10ld",sum1);
\x05}
\x05if(a>=2)
\x05{
\x05\x05sum2=1;
\x05\x05printf("M.2%10ld",sum2);
\x05}
\x05else
\x05\x05for(int i =3;i
问题解答:
我来补答展开全文阅读