问题描述: y=cos(x-π/3) y=cos(x-π/3) 求这两个三角函数的奇偶性 1个回答 分类:数学 2014-11-05 问题解答: 我来补答 y=cos(x-π/3) =cosx*cosπ/3+sinxsinπ/3y=cos(-x-π/3) =cos-x*cosπ/3+sin-xsinπ/3=cosx*cosπ/3-sinxsinπ/3非奇非偶 展开全文阅读