问题描述： 证明 0.0999 1个回答 分类：数学 2014-11-16 问题解答： 我来补答 [1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]>[1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)]1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)=(1/10)-(1/11)+(1/11)-(1/12)+.+(1/1000)-(1/1001)=(1/10)-(1/1001)=0.099[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)] 展开全文阅读
