求导数f(x)=(x+1)(2x+1)(3x+1)(4x+1)

问题描述:

求导数f(x)=(x+1)(2x+1)(3x+1)(4x+1)
求f'(-1/3)
请包含推导过程
1个回答 分类:数学 2014-12-02

问题解答:

我来补答
f`(x)=(x+1)`(2x+1)(3x+1)(4x+1)+(x+1)(2x+1)`(3x+1)(4x+1)+(x+1)(2x+1)(3x+1)`(4x+1)+(x+1)(2x+1)(3x+1)(4x+1)`
=(2x+1)(3x+1)(4x+1)+2(x+1)(3x+1)(4x+1)+3(x+1)(2x+1)(4x+1)+4(x+1)(2x+1)(3x+1)
将 x=-1/3代入得
f'(-1/3)=0+0+2/27+0=2/27
 
 
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