已知方程（2011x）平方-2010×2012x-1=0的较大根为m,方程x平方+2011x-2012=0的较

由方程一,
2011²x² - (2011² - 1)x - 1 = 0
即,2011²x² - 2011²x + x -1 = 0
2011²x(x-1) + (x-1) = 0
∴(x-1)(2011²x + 1) = 0
∴ x = 1 或 x = - 1/2011²
∴m = 1
由方程二,x² + 2011x - 2012 = 0
十字相乘,得
(x - 1)(x+2012) = 0
∴x = 1或 x = - 2012
∴n = - 2012
∴m-n = 1 - (-2012) = 2013