问题描述: 求定积分∫((1-x^2)^3)^0.5dx 积分区间为0到1 1个回答 分类:数学 2014-11-16 问题解答: 我来补答 令x = sinz,dx = cosz dz∫(0→1) (1 - x²)^(3/2) dx= ∫(0→π/2) cos³z * (cosz dz)= ∫(0→π/2) cos⁴z dz= (4 - 1)!/4!* π/2= 3!/4!* π/2= (3 * 1)/(4 * 2 * 1) * π/2= 3π/16 展开全文阅读