问题描述: 观察分析下列方程:1x+2/x=3;2.x+6/x=5;3.x+12/x=7;请利用他们所蕴含的规律,求关于. 1个回答 分类:数学 2014-10-10 问题解答: 我来补答 1、x+2÷x=3x²+2=3xx²-3x+2=0(x-1)(x-2)=0x=1或x=22、x+6÷x=5x²+6=5xx²-x+5=0(x-1)(x-5)=0x=1或x=53、x+12÷x=7x²+12=7xx²-7x+12=0(x-3)(x-4)=0x=3或x=4而:x+(n²+n)÷(x-3)=2n+4x(x-3)+(n²+n)=(2n+4)(x-3)x²-3x+n²+n=2nx+4x-6n-12x²-3x-2nx-4x+n²+n+6n+12=0x²-(2n+7)x+n²+7n+12=0x²-[(n+3)+(n+4)]x+(n+3)(n+4)=0[x-(n+3)][x-(n+4)]=0x=n+3或x=n+4 展开全文阅读